numpy如何获取array中数组元素的索引位置

numpy - 获取array中数组元素的索引

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 <span class="time">2017年08月05日 10:36:59</span>
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1. 函数原型

argwhere(array):找到非空数组array在满足某些条件下的索引,返回索引数组。

2. 应用

2.1 一维数组

返回一个一维数组,代表当前满足条件的元素出现的位置。

# -*- coding: utf-8 -*- 
import numpy as np 
 
arr = np.random.randint(0,10, (5,)) 
index = np.argwhere(arr < 5)
# -*- coding: utf-8 -*-
import numpy as np

arr = np.random.randint(0,10, (5,))
index = np.argwhere(arr < 5)

2. 2 二维数组

返回二维数组,代表当前满足条件的元素出现的位置。

# -*- coding: utf-8 -*- 
import numpy as np 
 
”“” 
arr = 
 9 3 7 0 
 3 4 2 4 
 3 6 4 4 
 
index = 
 0 1 
 0 3 
 1 0 
 1 1 
 1 2 
 1 3 
 2 0 
 2 2 
 2 3 
”“” 
arr = np.random.randint(0,10, (3,4)) 
index = np.argwhere(arr < 5)
# -*- coding: utf-8 -*-
import numpy as np

"""
arr = 
 9 3 7 0 
 3 4 2 4 
 3 6 4 4 

index = 
 0 1
 0 3
 1 0
 1 1
 1 2
 1 3
 2 0
 2 2
 2 3
"""

arr = np.random.randint(0,10, (3,4))
index = np.argwhere(arr < 5)

参考文献

http://blog.csdn.net/vernice/article/details/50990919

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作者:yuan0061原文地址:https://blog.csdn.net/yuan0061/article/details/80378575

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